A类继承了B类,在A构造函数时不能A(B m,B #include #include #include class CPoint{public:\x05CPoint(double a,double b){x=a;y=b;}\x05double getx(){return x;}\x05double gety(){return y;}\x05void show()\x05{cout
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![A类继承了B类,在A构造函数时不能A(B m,B #include #include #include class CPoint{public:\x05CPoint(double a,double b){x=a;y=b;}\x05double getx(){return x;}\x05double gety(){return y;}\x05void show()\x05{cout](/uploads/image/z/10401844-4-4.jpg?t=A%E7%B1%BB%E7%BB%A7%E6%89%BF%E4%BA%86B%E7%B1%BB%2C%E5%9C%A8A%E6%9E%84%E9%80%A0%E5%87%BD%E6%95%B0%E6%97%B6%E4%B8%8D%E8%83%BDA%EF%BC%88B+m%2CB+%23include+%23include+%23include+class+CPoint%7Bpublic%3A%5Cx05CPoint%28double+a%2Cdouble+b%29%7Bx%3Da%3By%3Db%3B%7D%5Cx05double+getx%28%29%7Breturn+x%3B%7D%5Cx05double+gety%28%29%7Breturn+y%3B%7D%5Cx05void+show%28%29%5Cx05%7Bcout)
A类继承了B类,在A构造函数时不能A(B m,B #include #include #include class CPoint{public:\x05CPoint(double a,double b){x=a;y=b;}\x05double getx(){return x;}\x05double gety(){return y;}\x05void show()\x05{cout
A类继承了B类,在A构造函数时不能A(B m,B
#include
#include
#include
class CPoint
{
public:
\x05CPoint(double a,double b){x=a;y=b;}
\x05double getx(){return x;}
\x05double gety(){return y;}
\x05void show()
\x05{cout
A类继承了B类,在A构造函数时不能A(B m,B #include #include #include class CPoint{public:\x05CPoint(double a,double b){x=a;y=b;}\x05double getx(){return x;}\x05double gety(){return y;}\x05void show()\x05{cout
不是这个问题,是你的CPoint类的构造函数都要求有参数.
在CPoint中增加一个不需要参数的构造函数就OK了