作业帮已知f(n)=sin[(n+1\2)π+π\4]+cos[(n-1\2)+π\4]+tan[(n+1)π+π\4],求f(2011)的值
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![已知f(n)=sin[(n+1\2)π+π\4]+cos[(n-1\2)+π\4]+tan[(n+1)π+π\4],求f(2011)的值](/uploads/image/z/11694646-46-6.jpg?t=%E5%B7%B2%E7%9F%A5f%28n%29%3Dsin%5B%28n%2B1%5C2%29%CF%80%2B%CF%80%5C4%5D%2Bcos%5B%28n-1%5C2%29%2B%CF%80%5C4%5D%2Btan%5B%28n%2B1%29%CF%80%2B%CF%80%5C4%5D%2C%E6%B1%82f%282011%29%E7%9A%84%E5%80%BC)
已知f(n)=sin[(n+1\2)π+π\4]+cos[(n-1\2)+π\4]+tan[(n+1)π+π\4],求f(2011)的值
已知f(n)=sin[(n+1\2)π+π\4]+cos[(n-1\2)+π\4]+tan[(n+1)π+π\4],求f(2011)的值
已知f(n)=sin[(n+1\2)π+π\4]+cos[(n-1\2)+π\4]+tan[(n+1)π+π\4],求f(2011)的值
应该是tan[(n+1)2+π\4]吧?