英语化学求分子式和试验试!A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular for

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/25 19:10:11
英语化学求分子式和试验试!A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular for

英语化学求分子式和试验试!A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular for
英语化学求分子式和试验试!
A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular formulas of the compound?(Type your answer using the format CO2 for CO2.)
empirical formula
________________
molecular formula
________________

英语化学求分子式和试验试!A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular for
m(C)=(16.01/44)*12=4.36636 (mg)
m(H)=(4.37/18)*2*1=0.48556 (mg)
m(O)=10.68-4.36636-0.48556=5.82808 (mg)
n(C);n(H);n(O)=(4.36636/12):(0.48556/1):(5.82808/16)=3;4;3
empirical formulas of the compound;
C3H4O3
M(C3H4O3)n=176.1,
so n=176.1/(12*3+4*1+18*3)=2
molecular formulas of the compound;
C6H8O6

empirical formula C3H4O3
molecular formula C6H8O6 (Vitamin C)
鉴于这个应该是比较初级的化学 上面的答案是对的 权作参考
其实具体分子式可以式很多种 比如
丙酮酸 C3H4O3 等等 很多种答案都是对的