解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 02:08:44
解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)

解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)
解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)

解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)
1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x的平方+11x-708)
1/x - 1/(x+1) +1/(x+1) - 1/(x+2) +1/(x+2) - 1/(x+3)+1/(x+3) - 1/(x+4)+1/(x+4)-1/(x+5)=5/(x^2+11x-708)
1/x-1/(x+5)= 5/(x^2+11x-708)
5/[x(x+5)]=5/(x^2+11x-708)
x^2+5x=x^2+11x-708 6x=708 x=118

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1/(x的平方+x)可以分解为1/x减去1/(x+1)以此类推。。。最后的1/(x的平方+9x+20)分解为1/(x+4)减去1/(x+5)。经过约分简化得:1/x减去1/(x+5)。即1/x-1/(x+5)=5/(x的平方+11x-708)。再化简x(x+5)=x的平方+11x-708,计算得x=118带入原方程检验是真根。