求 dy/dx=x+x^2/y+y^2,y(0)=1的特解

x^y-y^x=2,求dy/dx 求dy/dx=(x-y+5)/(x+y-2) (x^2)dy+（y^2)dx=dx-dy x^2+y^2=e^y求dy/dx 求dy/dx=x/y+(cosx/y)^2通解 已知x=y^2-4y,求dy/dx y=2x^2+x求dy/dx x=sin(y/x)+e^2 求dy/dx y=e^x/x^2+sin2x 求dy/dx 微分方程 dy/dx=(-2x)/y Y=2-sinx.求dy/dx及dy/dx|x=0 求微分方程dy/dx=x^2y^2 dy/dx=x^2+y^2,求微分方程 求dy/dx 当y=2^(x^2) 求dy/dx=x^2-y^2通解, 设x^2+y^2=4,求dy/dx 求通解:(xy-x^2)dy=y^2dx y=(2x-7)^5 求 dy/dx=?