,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,DH与AE,CG交于P,M,BF与AE,CG交于N,G,

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,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,DH与AE,CG交于P,M,BF与AE,CG交于N,G,

,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,DH与AE,CG交于P,M,BF与AE,CG交于N,G,
,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,
如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,DH与AE,CG交于P,M,BF与AE,CG交于N,G,
 求证:AB=AD+PQ

,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,如图:平行四边形ABCD中AB>AD,AE,BF,CG,DH是各内角的角平分线,分别交于CD,AB于E,F,G,H,DH与AE,CG交于P,M,BF与AE,CG交于N,G,
思路如下:
①先证AE∥CG,同理BF∥DH
②由△ADE等腰得DA=DE,
③由DP平分∠ADC得AP=EP,
④由△APO≌△CQB得AP=CQ,
⑤由四边形CEPQ是平行四边形得PQ=CE
∴AB=CD=DE+CE=AD+PQ