作业帮计算：[2-(1又2/3-4/5)*2]*(-6又1/3)
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 07:47:12
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计算：[2-(1又2/3-4/5)*2]*(-6又1/3)
计算：[2-(1又2/3-4/5)*2]*(-6又1/3)
计算：[2-(1又2/3-4/5)*2]*(-6又1/3)
[2-(5/3 -4/5)×2]×(-19/3)
=[2-(10/3- 8/5)]×(-19/3)
=[(30/15)-(50/15)+(24/15)]×(-19/3)
=(4/15)×(-19/3)
=-76/45
[2-(1又2/3-4/5)*2]*(-6又1/3)
=(2-13/15*2)*(-6又1/3)
=(2-26/15)*(-6又1/3)
=4/15*(-19/3)
=-76/45
=-1又31/45