若(x+y)(x-y)+4(y-1)可以分解为多项式A与B的积,则A=______,B______.

(x+y)(x-y)+4(y-1) （x+y)²-4(x+y-1) 因式分解:(x+y)-4(x+y-1) 若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值? 若x-y=1 化简（x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16) 若x+y=4,则多项式1/2(x+y)+4(x-y)-3（x-y）-3/2(x+y)-x+y值是（） 若(-x+6):(x-y):(4x+y)=3:14:1,求x+y 若(-x+6):(x-y):(4x+y)=3:14:1,求x+y x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 把4（x-y+1)+y(y-2x)因式分解 因式分解:(x+y)(x-y)+4(y-1) y(y+2)+4x(x-y-1)因式分解是多少 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 {(x,y) |x|+|y| x>y?x:y 证明：若x>0,y>0,x+y=1,则（x+1/x)(y+1/y)≥25/4 若x,y满足约束条件,x>=0,y>=0,x-y>=-1,3x+4y 若x-y=1,求代数式x(x-y)+y(y-x)+2013的值