数学8下题x^2+2x-3\x^2-x=

数学8下题x^2+2x-3\x^2-x=
数学8下题x^2+2x-3\x^2-x=

数学8下题x^2+2x-3\x^2-x=
(x²+2x-3)/(x²-x)
=[(x+3)(x-1)]/[x(x-1)]
=(x+3)/x
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(x^2+2x-3)/(x^2-x)
=(x-1)(x+3)/x(x-1)
=(x+3)/x

不会，我才初一

(x^2+2x-3)/(x^2-x)
=(x-1)(x+3)/x(x-1)
=(x+3)/x

用十字交叉法http://baike.baidu.com/view/749276.htm
化简得(x+3)/x