[50分]求定积分极限问题一则[解出50分加分]Find the limit,as n goes to infinity,of the integral from 1 to 2 of the functionf(x) = (cos x)(Arctan nx) 求lim(n->无穷大) [f(x)从1到2的积分]

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[50分]求定积分极限问题一则[解出50分加分]Find the limit,as n goes to infinity,of the integral from 1 to 2 of the functionf(x) = (cos x)(Arctan nx) 求lim(n->无穷大) [f(x)从1到2的积分]

[50分]求定积分极限问题一则[解出50分加分]Find the limit,as n goes to infinity,of the integral from 1 to 2 of the functionf(x) = (cos x)(Arctan nx) 求lim(n->无穷大) [f(x)从1到2的积分]
[50分]求定积分极限问题一则[解出50分加分]
Find the limit,as n goes to infinity,of the integral from 1 to 2 of the function
f(x) = (cos x)(Arctan nx)
求lim(n->无穷大) [f(x)从1到2的积分]

[50分]求定积分极限问题一则[解出50分加分]Find the limit,as n goes to infinity,of the integral from 1 to 2 of the functionf(x) = (cos x)(Arctan nx) 求lim(n->无穷大) [f(x)从1到2的积分]
其实学过实变的话用控制收敛定理的语言更好说一点,不过看样子你差不多应该是大一刚学而已.
那就用两边夹语言来说吧.
因为在1和2之间cosx都是正的,而Arctan nx单调而且都也为正的,所以Arctan n

怎么是英文题目啊 求翻译 我英语很差

lim(n->无穷大),f(x) = (cos x)(Arctan nx)=π/2 cos x
f(x)从1到2的积分=(π/2 sin x)∣=π/2(sin2-sin1)