a+a(x+1)+a(x+2)^2 化简.................是a+a(x+1)+a(x+1)^2

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a+a(x+1)+a(x+2)^2 化简.................是a+a(x+1)+a(x+1)^2

a+a(x+1)+a(x+2)^2 化简.................是a+a(x+1)+a(x+1)^2
a+a(x+1)+a(x+2)^2 化简
.................是a+a(x+1)+a(x+1)^2

a+a(x+1)+a(x+2)^2 化简.................是a+a(x+1)+a(x+1)^2
楼主,
原式=a+ax+a+ax²+4ax+4a
=ax²+5ax+6a
=a(x²+5x+6)
=a(x+2)(x+3)
按照补充的题是这样:
原式=a+ax+a+ax²+2ax+2a
=ax²+3ax+4a
=a(x²+3x+4)

a+a(x+1)+a(x+2)^2
=a[(x+2)^2+(x+1)+1]
=a[(x+2)^2+x+2]
=a(x+2)[(x+2)+1]
=a(x+2)(x+3)

原=a+ax+a+ax^2+4ax+4a
=a(x^2+5x+6)
=ax^2+5ax+6a