how to solve 16^X+4^X-20=0

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how to solve 16^X+4^X-20=0
how to solve 16^X+4^X-20=0

how to solve 16^X+4^X-20=0
设4^x为t,16^x=（4^x）²=t²,则
∴原式=t²+t-20=0
∴因式分解可得：
（t+5）（t-4）=0
∴t=4或t=-5
∵t=4^x＞0
∴t=4
∴4^x=4
∴x=1

16^X+4^X-20=0
即4^2X+4^X=20
得出x=1

16^X+4^X-20=0
16^X-16+4^X-4=0
16^X-16=0，4^X-4=0
x-1=0
x=1

x=1,（4 1）4^x=20

16*x+4*x-20=0
（16*x+4*x）=20
20*x=20
x=1

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