作业帮(求解、x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 07:49:14
(求解、x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
(求解、x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
(求解、x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
(x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
(x+5)/(x-1)-(3x-3)/(x+5)-(8x+28)/(x^2+4x-5)=-2
(x+5)^2/(x-1)(x+5)-3(x-1)^2/(x+5)-(8x+28)/(x+5)(x-1)=-2
[(x+5)^2-3(x-1)^2-(8x+28)]/(x+5)(x-1)=-2
[x^2+10x+25-3x^2+6x-3-8x-28]/(x+5)(x-1)=-2
[x^2-3x^2+10x+6x-8x+25-3-28]/(x+5)(x-1)=-2
(-2x^2+8x-6)/(x+5)(x-1)=-2
-2(x^2-4x+3)/(x+5)(x-1)=-2
(x^2-4x+3)/(x+5)(x-1)=1
x^2-4x+3=x^2+4x-5
4x+4x=3+5
8x=8
x=1
经检验x=1是方程的增根,所以方程无解
(x+5)/(x-1)-(3x-3)/(x+5)=(8x+28)/(x^2+4x-5)-2
左、右两边通分
((x+5)^2-3(x-1)^2)/((x-1)(x+5))=((8x-28)-2(x^2+4x-5))/((x-1)(x+5))
(x+5)^2-3(x-1)^2)=(8x-28)-2(x^2+4x-5)
x^2+10x+25-3x^2+6x-3=8x-28-2x^2-8x+10
-2x^2+16x-22=-2x^2+38
16x=16
x=1