化简sinα^6+cosα^6+3sinα^2cosα^2的结果是

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 08:27:46
化简sinα^6+cosα^6+3sinα^2cosα^2的结果是

化简sinα^6+cosα^6+3sinα^2cosα^2的结果是
化简sinα^6+cosα^6+3sinα^2cosα^2的结果是

化简sinα^6+cosα^6+3sinα^2cosα^2的结果是
原式=(sin²a+cos²a)(sin^4a-sin²acos²a+cos^4a)+3sin²acos²a
=sin^4a-sin²acos²a+cos^4a+3sin²acos²a
=sin^4a+2sin²acos²a+cos^4a
=(sin²a+cos²a)²
=1

sinα^6+cosα^6+3sinα^2cosα^2
=(sinα^2+cosα^2)(sinα^4-sinα^2cosα^2+cosα^4)+3sinα^2cosα^2
=sinα^4-sinα^2cosα^2+cosα^4+3sinα^2cosα^2
=sinα^4+2sinα^2cosα^2+cosα^4
=(sinα^2+cosα^2)^2
=1

化简sinα^6+cosα^6+3sinα^2cosα^2的结果是 化简:sin^6α+cos^6α+3sin^2α*cos^2α=? sin^6а+cos^6а+3sin²аcos²а化简=(sin^2α+cos^2α)(sin^4α-sin^2α*cos^2α+cos^4α)+3sin^2α*cos^2α这一步的sin四次方是怎么出来的?看不懂,求这一步的详写. 化简:cos(π/3+α)+sin(π/6+α) 2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)mingbaidian 2(sin^6 α +cos^6α)-3(sin^4a+cos^4α) 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin² 已知6sin²α+sinαcosα-2cos²α=0,α∈(π/2,π),求值1).(sinα-3cosα)/(sinα-cosα);2).sinαcosα-sin²α;3).sin²α-3cosαsinα-2 1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第三象限角,求sin(β+5π/4)的值.3.化简sin(α-β)sin(β-λ)-cos(α-β)cos(λ-β) 6sin^2α-sinαcosα-cos^2α=0,求cosα+sinα的值 化简√3sinα-cosα sinα+cosα 化简 已知2sin平方α-cos平方α+sinαcosα-6sinα+3cosα=0,求(2cos平方α+2sinαcosα)/1+tanα的值 三角函数题2sin^2α-cos^α+sinα*cosα-6sinα+3cosα=0 求(2cos^α+2sinαcosα)/1+tanα 求(6sinα+cosα)/(3sinα-2sinα)的值 tan(α/2)=2求值 三角函数求解!难题我采纳!10.化简.(1)【sin(2π-α)cos([π/2]+α)cos([π/2]-α)】/【sin(3π-α)sin(-π-α)sin([π/2]+α)】(2)【an(2π-θ)sin(2π-θ)cos(6π-θ)】/【(-cosθ)sin(5π+θ)】11.已知tanα=-2,求sin^2α-4sinαcos