已知xy为实数,且满足4x^2+8x-(y-1)根号1-y+4=0,那么x^2013-y^2013

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已知xy为实数,且满足4x^2+8x-(y-1)根号1-y+4=0,那么x^2013-y^2013

已知xy为实数,且满足4x^2+8x-(y-1)根号1-y+4=0,那么x^2013-y^2013
已知xy为实数,且满足4x^2+8x-(y-1)根号1-y+4=0,那么x^2013-y^2013

已知xy为实数,且满足4x^2+8x-(y-1)根号1-y+4=0,那么x^2013-y^2013
答:
x和y都是实数,满足:
4x^2+8x-(y-1)√(1-y)+4=0
4(x+1)^2=(y-1)√(1-y)>=0…………(1)
所以:
y-1>=0
1-y>=0
解得:y=1
代入(1)解得:x+1=0,x=-1
x^2013-y^2013
=(-1)^2013-1^2013
=-1-1
=-2