作业帮200分求数学题 求过程A block of steel on a level, frozen pond, is given an initial speed V. Even though the block of steel issliding on smooth ice, there will be a small friction force that will slow the block of steel until itcomes to a stop.
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200分求数学题 求过程A block of steel on a level, frozen pond, is given an initial speed V. Even though the block of steel issliding on smooth ice, there will be a small friction force that will slow the block of steel until itcomes to a stop.
200分求数学题 求过程
A block of steel on a level, frozen pond, is given an initial speed V. Even though the block of steel is
sliding on smooth ice, there will be a small friction force that will slow the block of steel until it
comes to a stop. Assume that the distance, d, the block travels is directly proportional to the
square of V. When V = 4 feet per second, d = 32 feet. Find the distance the block travels if the
initial speed is 10 feet per second.
答案为200feet 求过程
200分求数学题 求过程A block of steel on a level, frozen pond, is given an initial speed V. Even though the block of steel issliding on smooth ice, there will be a small friction force that will slow the block of steel until itcomes to a stop.
Assume that the distance,d,the block travels is directly proportional to the
square of V
译为,d和V^2成正比,
即d/V^2的值是一常数
已知V=4,d=32
要知道V=10的时候,d=?
d/V^2=d/V^2
左边是V=10,d未知
右边是V=4,d=32
即d/10^2=32/4^2
d/100=32/16=2
d=100*2=200 feet
d与 V的平方成比例：设d=kV^2 由 V = 4 feet per second, d = 32 feet得k=2
即：d=2V^2 当V=10时，d=2×10^2=200
Assume that the distance, d, the block travels is directly proportional to the
square of V
译为，d和V^2成正比,
即d/V^2的值是一常数
已知V=4, d=32
这道题大致可以翻译为
钢块在冰上滑行的距离为d，速度是v，且d与v的平方成正比，当v=4的时候，d=32，则求当d=32的时候，钢块在冰面上滑行的距离
解题过程：因为d与v的平方成正比，假设比值为a，既有d/v²=a ，因为v=4时，d=32，可以解得a=2
所以有公式d/v²=2，所以当v=10的时候，带入公式可以解得d=200
可以明白？...
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这道题大致可以翻译为
钢块在冰上滑行的距离为d，速度是v，且d与v的平方成正比，当v=4的时候，d=32，则求当d=32的时候，钢块在冰面上滑行的距离
解题过程：因为d与v的平方成正比，假设比值为a，既有d/v²=a ，因为v=4时，d=32，可以解得a=2
所以有公式d/v²=2，所以当v=10的时候，带入公式可以解得d=200
可以明白？
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shit and fuck bitch
you known??