model:sets:month/1..12/:pro,sel,sto;endsetsmin=@sum(month:5*pro);@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));sto(0)=0;sto(12)=2;@for(month(i):sto(i)

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model:sets:month/1..12/:pro,sel,sto;endsetsmin=@sum(month:5*pro);@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));sto(0)=0;sto(12)=2;@for(month(i):sto(i)

model:sets:month/1..12/:pro,sel,sto;endsetsmin=@sum(month:5*pro);@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));sto(0)=0;sto(12)=2;@for(month(i):sto(i)
model:
sets:
month/1..12/:pro,sel,sto;
endsets
min=@sum(month:5*pro);
@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));
sto(0)=0;
sto(12)=2;
@for(month(i):sto(i)

model:sets:month/1..12/:pro,sel,sto;endsetsmin=@sum(month:5*pro);@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));sto(0)=0;sto(12)=2;@for(month(i):sto(i)
lingo里面下标都从1开始 你怎么写出来sto(0)
另外你自己看清楚 即使有这个 那么 pro(0)需不需要 如果需要为什么没写

sto(0)应该是从1开始的,不是0;

这个 不太好说啊 都忘得 差不多了

model:sets:month/1..12/:pro,sel,sto;endsetsmin=@sum(month:5*pro);@for(month(i):sto(i+1)=(sto(i)+pro(i)-sel(i)));sto(0)=0;sto(12)=2;@for(month(i):sto(i) lingo编程出问题了model: sets: month/7..12/:x,y,w,c,d; endsetsmax=@sum(month(i):c(i)*y(i)-d(i)*x(i)-0.5*w(i));@for(month(i):w(i)=300;也有问题,错误代号70 Egypt sets six-month target for elections,求标题翻译, 英语仿造例子写句子model:you/last monthwhere were you last month?1.Ben/last summer2.they/testerday lingo程序:model:sets:product/1..3/:a,b; row/1..5/:c,d,y; num/1..9/:x; endsets其中的product和num该怎么用?还有平时不是用的col么而不是num区别在哪? 求大神改一下lingo程序model:sets:time/1..51/:t;rongliang/1..51/:r;link(time,rongliang):x;endsetsmin=@sum(time:t);@for(link:@bin(x));@for(link:@sum(link:x(i,j)*r) LINGO中的目标函数的表示若已知条件model:sets:a/1..5/:q;b/1..10/:y;c(a,b):x;endsets若要表示的目标函数为:该如何在lingo中表示出来? LINGO中的目标函数的表示方法若已知model:sets:a/1..5/:q;b/1..10/:y;c(a,b):x;endsets若要表示的目标函数为:该如何在lingo中表示出来? lingo错误model:sets:quarter/1..4/:DEM,RP,OP,INV;endsetsdata:DEM=40,60,75,25;enddatamin=@sum(quarter:400*RP+450*OP+20*INV);@for(quarter(I):RP lingo找错model:sets:quarters/1..45/xr,yr,wr,zr,tr;endsetsmin=@sum(quarters(i):xr(i)*zr(i)*tr(i));@sum(quarters(i):xr(i)*yr(i))>=5320;@sum(quarters(i):xr(i)*wr(i)) lingo运行错误improper use of attribute name,model:sets:chan/c1..c10/:p,q,w,f;xie/1..5/:d;links(chan,xie):x,c,l,a,b,t;endsets@for(chan(i):@sum(xie(j):x(i,j)) model:sets:year/1..3/:demand,new,nature,gouxie; gou/1..8/:pay,xie; link(year,gou):c; endsets datamodel:sets:year/1..3/:demand,new,nature,gouxie;gou/1..8/:pay,xie;link(year,gou):c;endsetsdata:demand=150,160,170;nature=46.15,41.55,37.12;pay=5,7,5,4,6,5 model:title Location problem; sets:demand/1..6/:a,b,d; supply/1,2/:x,y,e; link(demand,supply):c; e照书上写的,还是出错了.大惑不解.错误代码:50for函数使用不当所用版本为lingo11model:title Location problem;sets:demand/1..6/: 小弟刚接触LINGO,实在是没辙了,编写完成后出现model is ill difined希望各位好心人帮助,十万火急,谢谢model:sets:DMU/1..14/:H,W;II/1..2/;OI/1..2/; IV(II,DMU):X;OV(OI,DMU):Y; endsetsdata:X=0.37418 0.144448 0.106145 0.122964 model is ill lingo,高手帮帮忙!1下面的是我写的 但是怎么改都有错!model:sets: varei/1..7/:t,s; varej/1..4/:size,num,p1,p2,g,b,q; links(varei,varej):x,p,m,d;endsets!目标函数;min=@sum(links:m(i,j)*((p(i,j)-p1(j))*b(j)+g(j))*t(i) lingo提示MODEL IS ILL DEFINED.model:sets:project/1..7/;year/1..5/;assignment(project,year):a,b,c,d,e,x;endsetsdata:a=360,600,400,950,10.5,6.8,7.0,360,600,400,1350,10.5,6.8,7.0,360,600,400,1350,10.5,6.8,7.0,360,600,400,950,10.5,6.8,7.0,360,600,400,1 lingo 错误的1017我在model后面打过:model:sets:para/1..3/:y;warehouses/wh1..wh3/:capacity;vendors/v1..v4/:demand;links(warehouses,vendors):cost,volume;endsets目标函数;min=@sum(links:cost*volume)+91y(1)+70y(2)+24y(3);@for(para:@bin(y)); 我在使用lingo时出现THE MODEL DIMENSIONS EXCEED THE CAPACITY OF THIS VERSION.哪位大虾可以告诉我是什么地方出了问题.如何解决,程序应该不用出错.谢谢.程序如下:model:title CUMCM-2003B-01;sets:cai / 1..10 /:crate,