若数列an满足a1=3,a(n+1)=-1/an+1,则a2012=

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若数列an满足a1=3,a(n+1)=-1/an+1,则a2012=

若数列an满足a1=3,a(n+1)=-1/an+1,则a2012=
若数列an满足a1=3,a(n+1)=-1/an+1,则a2012=

若数列an满足a1=3,a(n+1)=-1/an+1,则a2012=
a2=-1/(a1+1)=-1/4
a3=-1/(a2+1)=-4/3
a4=-1/(a3+1)=3=a1
an是周期数列
2012被4整除
∴a2012=a1=3
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