(x+2)(2x-3)(x-5)>30解高次不等式

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(x+2)(2x-3)(x-5)>30解高次不等式

(x+2)(2x-3)(x-5)>30解高次不等式
(x+2)(2x-3)(x-5)>30
解高次不等式

(x+2)(2x-3)(x-5)>30解高次不等式
展开再把30移到左边化成关于0的不等式 得
2x^3-9x^2-11x>0
所以 x(x+1)(2x-11)>0
有3个零点x=-1 x=0 x=11/2
再由串根法解得(-1,0)并(11/2,正无穷)

(x+2)(2x-3)(x-5)>30
(2x^2+x-6)(x-5)>30
2x^3-9x^2-11x+30>30
2x^3-9x^2-11x>0
x(2x^2-9x-11)>0
x(x+1)(2x-11)>0
-111/2

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