已知Ia-b+3I+(a-2)^2=0,求7ab^2+[(4ab-8a^2b+4)-2ab^2]的值

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已知Ia-b+3I+(a-2)^2=0,求7ab^2+[(4ab-8a^2b+4)-2ab^2]的值
已知Ia-b+3I+(a-2)^2=0,求7ab^2+[(4ab-8a^2b+4)-2ab^2]的值

已知Ia-b+3I+(a-2)^2=0,求7ab^2+[(4ab-8a^2b+4)-2ab^2]的值
解
/a-b+3/+(a-2)²=0
∴a-b+3=0.a-2=0
∴a=2,b=5
∴7ab²+[(4ab-8a²b+4)-2ab²]
=7ab²+(4ab-8a²b+4-2ab²)
=(7ab²-2ab²)-8a²b+4ab+4
=5ab²-8a²b+4ab+4
=5×2×25-8×4×5+4×2×5+4
=250-160+40+4
=130+4
=134

由Ia-b+3I+(a-2)^2=0,得
a-b+3=0 a-2=0
所以a=2 b=5
于是7ab^2+[(4ab-8a^2b+4)-2ab^2]=7*2*25+[（4*2*5-8*4*5+4）-2*2*25]=134

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