作业帮计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 20:59:36
![计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}](/uploads/image/z/8834478-6-8.jpg?t=%E8%AE%A1%E7%AE%97%2C%E4%BE%9D%E6%8D%AE%E5%9B%BE%E7%89%87%3A%7B%28x%5E2%2Byz%29%C3%B7%5Bx%5E2%2B%28y-z%29x-yz%5D%7D%2B%7B%28y%5E2%2Bzx%29%C3%B7%5By%5E2%2B%28z%2Bx%29y-zx%5D%7D%2B%7B%28z%5E2%2Bxy%29%C3%B7%5Bz%5E2-%28x-y%29z-xy%5D%7D)
计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}
计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}
计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}
(x^2+yz)/x^2+(y-z)x-yz={x^2+xy/(x+y)(x-z)}+{yz-xy/(x+y)(x-z)}=(x/x+z)-(y/x+y)
每个都这样化 或许会解出来
我也在做
计算,依据图片:{(x^2+yz)÷[x^2+(y-z)x-yz]}+{(y^2+zx)÷[y^2+(z+x)y-zx]}+{(z^2+xy)÷[z^2-(x-y)z-xy]}
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