若x=π/12,则(cosx)^6-(sinx)^6等于

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若x=π/12,则(cosx)^6-(sinx)^6等于

若x=π/12,则(cosx)^6-(sinx)^6等于
若x=π/12,则(cosx)^6-(sinx)^6等于

若x=π/12,则(cosx)^6-(sinx)^6等于
(cosx)^6-(sinx)^6
=[(cosx)^3+(sinx)^3][(cosx)^3-(sinx)^3]
=(cosx+sinx)*(cos^2x-sinxcosx+sin^2x)(cosx-sinx)(cos^2x+sinxcosx+sin^2x)
=(cosx+sinx)(cosx-sinx)(1-1/2sin2x)(1+1/2sin2x)
=(cos^2x-sin^2x)(1-1/2sin2x)(1+1/2sin2x)
=cos2x*[1-1/4sin^2(2x)]
=cosπ/6*(1-1/4sin²π/6)
=√3/2×(1-1/4×1/4)
=√3/2×15/16
=15√3/32

cos2x=√3/2,sin2x=1/2
原式=(cos²x-sin²x)[(cosx)^4+sin²xcos²x+(sinx)^4]
=cos2x[(sin²x+cos²x)²-sin²xcos²x]
=cos2x[1-1/4*sin²2x]
=15√3/32